After The School
Class 10PhysicsChapter 10: Light — Reflection and Refraction

10.2 Spherical Mirrors

Mirror formula, magnification, sign convention, and worked example for spherical mirrors.

Spherical Mirrors

A spherical mirror is a mirror whose reflecting surface is a part of a sphere.

TermSymbolDescription
Centre of curvatureCCCentre of the sphere of which the mirror is a part
Radius of curvatureRRRadius of that sphere
Focal lengthffDistance from pole to principal focus
PolePPCentre of the reflecting surface

Relation between ff and RR

For a spherical mirror of small aperture:

f=R2f = \frac{R}{2}

Mirror Formula

1v+1u=1f\frac{1}{v} + \frac{1}{u} = \frac{1}{f}

where:

  • uu = object distance
  • vv = image distance
  • ff = focal length

Magnification

m=hh=vum = \frac{h'}{h} = -\frac{v}{u}

where hh' is the height of the image and hh is the height of the object.

Sign Convention (New Cartesian)

  • All distances are measured from the pole (PP).
  • Distances in the direction of the incident ray are positive.
  • Distances opposite to the incident ray are negative.
  • Heights above the principal axis are positive; below are negative.

Example

A concave mirror has a focal length of 15cm15\,\text{cm}. An object is placed 30cm30\,\text{cm} in front of it. Find the image position and magnification.

Given: f=15cmf = -15\,\text{cm}, u=30cmu = -30\,\text{cm}

1v=1f1u=115130=115+130=130\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{-15} - \frac{1}{-30} = -\frac{1}{15} + \frac{1}{30} = -\frac{1}{30} v=30cmv = -30\,\text{cm}

The image is formed at 30cm30\,\text{cm} in front of the mirror (real, inverted).

m=vu=3030=1m = -\frac{v}{u} = -\frac{-30}{-30} = -1

The image is the same size as the object and inverted.